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Our admissions department will be happy to help you with your questions and concerns. We hope you choose Harris for your surgical technician education.
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#1 Hello, I would like to know if there is any formulea for calculating the peak current through an inductor, i am under the impression that when a voltage is passed across an inductor, the properties of the inductor limit the current. I know ohms law will work for resistors etc. I am using the inductor as a coilgun, its resistance is 1. 2Ω and inductance is 1. 315mH, it was wound with half a pound of 18SWG wire(not sure how many turns? ) I am discharging 200V from a capcitor bank of 2000uF. Thank You. #2 ZIGGY_DAN said: The "Ohm's law" for inductance is v = L di/dt where v is the voltage across the inductor, L is the inductance, i is the current and t is time. For capacitance it is i = C dv/dt. So if you understand calculus, you can write a differential equation that, when solved, will allow you to calculate the current. If your maths is not up to the task, then use a circuit simulation programme such as Switcher CAD III. #3 Thanks ljcox, my maths is pretty good (I think, lol) i'll write those down and see what values i can come up with, i am assuming it is: V in Volts I in Amperes L in Henrys D in Metres T in Seconds When I rearrange it i get I= ( (V*D*T) /L) /D Is this right??
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